Assume that the Moon is in circular orbit around the Earth. The distance between the Moon and the Earth is approximately 3.56 * 106 km. The period of the Moon's orbit is approximately 28 days. What is the acceleration of the Moon in km / h2?

Acceleration = 311.2 Km/hr²

Explanation:

Given: Radius of the Orbit r = 3.56 * 10⁶ km

Period of the orbit = 28 days = 672 hrs

Sol: We have Fc = MV²/r

⇒M ac = MV²/r

⇒ac = V²/r

First we have to Speed V so for this we have to find the circumference (distance covered by the moon in one orbit)

⇒ Circumference = 2 π r

= 2 * 3.13149 * 3.56 * 10⁶ km

= 22,368,139.69 Km

Now Speed = Distance / time

Speed = 22,368,139.69 Km / 672 hrs

Speed V = 33,285.92 Km/Hr

Now

ac = V²/r = (33,285.92 Km/hrs) ² / 3.56 * 10⁶ km

ac = 311.2 Km/hr²