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3 August, 22:29

An object with mass 110 kg moved in outer space. When it was at location its speed was 19.5 m/s. A single constant force N acted on the object while the object moved to location m. What is the speed of the object at this final location

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  1. 3 August, 23:42
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    v = 21.4m/s

    Explanation:

    Given r1 = m,

    F = N, r2 = m

    Where r1 and r2 are position vectors in space and F is the constant force vector in space.

    r2 - r1 = m

    Δr = m

    F = m*a

    a = F/m

    m = 110kg (scalar quantity)

    a =

    a = m/s²

    Since the force is constant, the acceleration is also constant. Therefore the equations of constant acceleration motion apply here.

    V² = u² + 2aΔr

    The magnitude of the acceleration is calculated as follows

    a = √ (2.27² + 3.55² + (-2) ²)

    a = √ (21.7554)

    a = 4.66m/s²

    Magnitude of Δr,

    Δr = √ (6² + (-5) ² + (-3) ²) = √ (70) = 8.37m

    Having calculated the magnitude of the acceleration and displacement, we can now calculate the final velocity.

    u = initial velocity = 19.5m/s

    v² = 19.5² + 2*4.66*8.37

    v² = 458.25

    v = √ (458.25)

    v = 21.4m/s
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