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28 October, 02:34

5. Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goal post and experiences a backward force of 1.76 x 104 N for 5.50 x 10-2 s.

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  1. 28 October, 04:54
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    0.8 m/s

    Explanation:

    From Newton's third law of motion,

    Impulse on a body = Change in momentum of the body

    Ft = m (v-u) ... Equation 1

    Where F = force on the body, t = time, m = mass of the body, v = final velocity, u = initial velocity,

    Note: Taking the direction of the initial velocity as negative,

    Given: F = 1.76*10⁴ N, t = 5.5*10⁻² s, m = 110 kg, u = - 8.0 m/s

    Substitute into equation 1

    1.76*10⁴ (5.5*10⁻²) = 110[v - (-8.0) ]

    968 = 110v+880

    110v = 968-880

    110v = 88

    v = 88/110

    V = 0.8 m/s

    Hence the final velocity = 0.8 m/s
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