A fish swimming behind an oil tanker gets caught in a whirlpool created by the ship's propellers. The fish has an initial angular speed of 0.70 rad/s. After 4.3 s, the fish's angular speed is 13.7 rad/s. If the water in the whirlpool accelerates at a constant rate, what is the angular acceleration? Answer in units of rad/s 2.

Answer: 3.02 rad/s²

Explanation: The motion of the fish is of a constant angular acceleration, hence it motion can be described by using the equation of motion of a constant angular acceleration.

ω = ω' + αt

Where ω = final angular speed = 13.7rad/s ω' = initial angular speed = 0.7rad/s α = angular acceleration = ?

time = 4.3s

13. 7 = 0.7 + (4.3) α

13.7 - 0.7 = 4.3α

13 = 4.3α

α = 13 / 4.3

α = 3.02 rad/s²