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22 August, 20:21

A rectangular block of copper has sides of length 15 cm, 26 cm, and 43 cm. If the block is connected to a 5.0 V source across two of its opposite faces, find the following. (a) What is the maximum current the block can carry?

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  1. 22 August, 21:02
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    the case is the one with the greatest current, L=15 cm, i = 2.19 10⁸ A

    Explanation:

    Ohm's law is

    V = i R

    Resistance is

    R = ρ L / A

    Where L is the length of the electrons pass and A the area perpendicular to the current

    i = V / R

    i = V (A / ρ L)

    i = V / ρ (A / L)

    We can calculate the relationship between the area and the length to know in which direction the maximum currents

    Case 1

    L = 0.15 m

    A = 0.26 0.43 = 0.1118 m2

    A / L = 0.1118 / 0.15

    A / L = 0.7453 m

    Case 2

    L = 0.26 m

    A = 0.15 0.43 = 0.0645 m2

    A / L = 0.248 m

    Case 3

    L = 0.43 m

    A = 0.15 0.26 = 0.039 m2

    A / L = 0.0907 m

    We can see that the case is the one with the greatest current, L=15 cm

    Let's calculate the current

    i = 5 / 1.7 10⁻⁸ (0.7453)

    i = 2.19 10⁸ A
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