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9 February, 00:52

A parallel-plate capacitor is formed from two 1.6 cm - diameter electrodes spaced 2.8 mm apart. The electric field strength inside the capacitor is 6.0 * 10^6 N/C. What is the charge (in nC) on each electrode?

Express your answer using two significant figures.

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Answers (1)
  1. 9 February, 03:44
    0
    12 nC

    Explanation:

    Capacity of the parallel plate capacitor

    C = ε₀ A/d

    ε₀ is constant having value of 8.85 x 10⁻¹², A area of plate, d is distance between plate

    Area of plate = π r²

    = 3.14 x (0.8x 10⁻²) ²

    = 2 x 10⁻⁴

    C = (8.85 X 10⁻¹² x 2 x 10⁻⁴) / 2.8 x 10⁻³

    = 7.08 x 10⁻¹³

    Potential difference between plate = field strength x distance between plate

    = 6 x 10⁶ x 2.8 x 10⁻³

    = 16.8 x 10³ V

    Charge on plate = CV

    =7.08 x 10⁻¹³ X 16.8 X 10³

    11.9 X 10⁻⁹ C

    12 nC.
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