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31 August, 06:16

A 2.1 times 103 - kg car starts from rest at the top of a 5.0 - m - long driveway that is inclined at 20 deg with the horizontal. If an average friction force of 4.0 times 103 N impedes the motion, find the speed of the car at the bottom of the driveway.

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  1. 31 August, 07:05
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    speed of the car at the bottom of the driveway is 3.8 m/s

    Explanation:

    given data

    mass = 2.1 * 10³ kg

    distance = 5 m

    angle = 20 degree

    average friction force = 4 * 10³ N

    to find out

    find the speed of the car at the bottom of the driveway

    solution

    we find acceleration a by force equation that is

    force = mg*sin20 - friction force

    ma = mg*sin20 - friction force

    put here value

    2100a = 2100 (9.8) * sin20 - 4000

    a = 1.447 m/s²

    so from motion of equation

    v²-u² = 2as

    here u is 0 by initial speed and v is velocity and a is acceleration and s is distance

    v²-0 = 2 (1.447) (5)

    v = 3.8

    speed of the car at the bottom of the driveway is 3.8 m/s
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