What is the rate at which work is done in lifting a 35-kilogram object vertically at a constant speed of 5.0 meters per second?

1.75 kW

Explanation:

First, the rate at which work is done is simply termed Power

m = 35kg

v = 5.0 m/s

since the undergoes a vertical motion g = 10 m/s²

F = W = mg = 35*10 = 350 N

Power = Fv = 350*5 = 1750 Watt