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29 July, 15:30

An object of mass 0.77 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed of 16.2 m/s. Find the magnitude (in N) of the average force acting on the object during the 2.9 ms time interval. (Enter a number.)

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  1. 29 July, 18:14
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    Answer: 4.3KN

    Explanation:f=m (v-u) / t

    m=0.77kg

    t=0.0029s

    s=16.2m/s

    F = 0.77*16.2/0.0029

    F=12.474/0.0029

    F = 4301.38N

    F=4.3KN
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