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29 February, 08:50

A 28-kg beginning roller skater is standing in front of a wall. By pushing against the wall, she is propelled backward with a velocity of - 1.2 m/s. While pushing, her hands are in contact with the wall for 0.80 s. Ignoring frictional effects, find the magnitude and direction of the impulse acting on the skater.

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  1. 29 February, 11:48
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    33.6 Ns backward.

    Explanation:

    Impulse: This can be defined as the product of force and time. The S. I unit of impulse is Ns.

    From Newton's second law of motion,

    Impulse = change in momentum

    I = mΔv ... Equation 1

    Where I = impulse, m = mass of the skater, Δv = change in velocity = final velocity - initial velocity.

    Given: m = 28 kg, t = 0.8 s, Δv = - 1.2-0 = - 1.2 m/s (Note: the initial velocity of the skater = 0 m/s)

    Substituting into equation 1

    I = 28 (-1.2)

    I = - 33.6 Ns

    Thus the impulse = 33.6 Ns backward.
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