Ask Question
13 June, 12:07

The height of a cylinder is decreasing at a constant rate of 8 inches per minute, and the volume is decreasing at a rate of 161 cubic inches per minute. At the instant when the height of the cylinder is 66 inches and the volume is 919 cubic inches, what is the rate of change of the radius? The volume of a cylinder can be found with the equation V=/pi r^2 h. V=πr 2 h. Round your answer to three decimal places.

+3
Answers (1)
  1. 13 June, 15:46
    0
    0.056 inches per minute

    Explanation:

    dh/dt = 8 inches per minute

    dV/dt = 161 cubic inch per minute

    h = 66 inches

    V = 919 cubic inch

    dr/dt = ? rate of change of radius

    The volume of cylinder is given by

    V = πr²h

    where, r be the radius of cylinder

    Differentiate both sides with respect to t

    dV/dt = πr² x dh/dt + πh x 2r dr/dt ... (1)

    When h = 66 inches, V = 919 cubic inches

    So, 919 = 3.14 x r² x 66

    r = 2.11 inch

    Substitute the values in equation (1)

    161 = 3.14 x 2.11 x 2.11 x 8 + 3.14 x 66 x 2 x 2.11 x dr/dt

    dr/dt = 0.056 inches per minute
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The height of a cylinder is decreasing at a constant rate of 8 inches per minute, and the volume is decreasing at a rate of 161 cubic ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers