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10 June, 05:38

the volume of an iron sphere is 3.00cm cubed after being heated from 20.0c to 600.0 c what was the initial volume of the iron sphere at 20.0c

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Answers (2)
  1. 10 June, 06:05
    0
    V = 2.94cm³

    The initial volume at 20°C is 2.94cm³

    Explanation:

    As the temperature of the iron sphere increases the volume of the sphere also increase.

    Using the equation for volumetric expansion:

    ∆V = VαΔT

    where;

    V is the initial volume

    α is the volumetric expansion coefficient

    ∆V is the change in Volume

    ∆T is the change in temperature

    After Expansion the final volume can be written as:

    Vf = V + ∆V

    Vf = V + VαΔT

    Vf = V (1 + αΔT)

    making V the subject of formula;

    V = Vf / (1+αΔT) ... 1

    Given:

    Vf = 3.00cm³

    ΔT = 600-20 = 580

    And from the test book.

    α = 35.5 * 10⁻⁶K⁻¹

    Substituting the values into eqn 1

    V = 3.00 / (1+580 * 35.5*10^-6)

    V = 3.00 / (1+0.021) = 3.00/1.021

    V = 2.94cm³

    The initial volume at 20°C is 2.94cm³
  2. 10 June, 08:15
    0
    Answer: 1cm3

    Explanation:

    V1 = ?

    V2 = 3cm3

    T1 = 20°C = 20 + 273 = 293K

    T2 = 600°C = 600 + 273 = 873K

    V1 / T1 = V2 / T2

    V1 / 293 = 3 / 873

    V1 = 293 x (3 / 873)

    V1 = 1 cm3
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