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21 March, 10:32

The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitted. If the wavelength of the emitted gamma ray is 3.44*10-12 m, what is the decrease in mass, ΔmXe, of the xenon nucleus as a result of this decay?

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  1. 21 March, 13:50
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    Answer:3.87*10^-4

    Explanation:

    What is the decrease in mass, delta mass Xe, of the xenon nucleus as a result of this deca

    We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.

    C=f*lambda

    3*10^8=f*3.44*10^-12

    F=0.87*10^20 hz

    Then with the frequency, find the energy emitted using equation

    E=hf E = freq*Plank's constant

    E=.87*10^20*6.62*10^-34

    E=575.94*10^ (-16)

    With this energy, convert into MeV from joules.

    With the energy in MeV, use E=mc^2 using c^2 = 931.5 MeV/u.

    Plugging and computing all necessary numbers gives you

    3.87*10^-4 u.
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