The temperature of 1 m^3 of water is decreased by 10°C. If this thermal energy is used to lift the water vertically against gravity, what is the change in height of the center of mass?

h = 4271.43 m

Explanation:

given,

Volume of the water = 1 m³

temperature decrease by = 10°C

heat removed from water

Q = m c ΔT

Q = ρ V c ΔT

= 1000 * 1 * 4186 * 10

= 4.186 * 10⁷ J

energy is used to do work to move the water against its weight

Q = force * displacement

4.186 * 10⁷ J = m g * h

4.186 * 10⁷ J = 1000 * 1 * 9.8 * h

h = 4271.43 m

hence, the change in height of is equal to h = 4271.43 m