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11 February, 08:18

A car traveling 85 km/h slows down at a constant 0.53 m/s^2 just by "letting up on the gas." Calculate the distance it travels during the first second.

Calculate the distance it travels during the fifth second.

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  1. 11 February, 08:46
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    a) d = 23.345 m : distance the car travels in the first second

    b) d = 111.425 m : distance the car travels in the fifth second

    Explanation:

    The distance (d) in uniformly accelerated motion is calculated as follows:

    d = v₀*t + (1/2) * a*t² Formula (1)

    d: distance (m)

    v₀: initial speed (m/s)

    a: acceleration (m/s²)

    t: time (s)

    Equivalences

    1 km = 1000m

    1 h = 3600 s

    Data

    v₀ = 85 km/h = 85*1000m/3600s = 23.61 m/s

    a = - 0.53 m/s²

    Calculation of the distance the car travels in the first second

    We replace data in formula (1) at t = 1s

    d = 23.61 * (1) + (1/2) * (-0.53) * (1) ²

    d = 23.345 m

    Calculation of the distance the car travels in the fifth second

    We replace data in formula (1) at t = 5s

    d = 23.61 * (5) + (1/2) * (-0.53) * (5) ²

    d = 111.425 m
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