Ask Question
25 October, 08:03

A copper block with a mass of 300 grams is cooled to 77K by being immersed in liquid nitrogen. The block is then placed in a Styrofoam cup containing some water that is initially at + 50.0°C. Assume no heat is transferred to the cup or the surroundings. The specific heat of liquid water is 4186 J / (kg °C), of solid water is 2060 J / (kg °C), and of copper is 385 J / (kg °C). The latent heat of fusion of water is 3.35 x 105 J/kg. When the system comes to equilibrium, the temperature is 0°C. (a) Calculate the maximum possible mass of water that could be in the cup. (g) (b) Calculate the minimum possible mass of water that could be in the cup. (g)

+5
Answers (1)
  1. 25 October, 10:02
    0
    mass of copper block = 0.3 kg at 77 K or - 196 °C

    Let mass of water taken be m (maximum), in this case we will have mixture of water and copper block at 0°C finally.

    Heat gained by copper block

    = msΔt

    .3 x 196 x 385 J

    heat lost by water to lower its temp fro 50°C to 0°C

    = m x 4186 x 50

    Heat lost = heat gained

    m x 4186 x 50 =.3 x 196 x 385

    m = 108.16 gm

    Let mass of water taken be m (minimum), in this case we will have mixture of ice and copper block at 0°C finally.

    heat lost by water to lower its temp fro 50°C to 0°C

    = m x 4186 x 50

    heat lost by water to lower its temp from 0°C to 0°C ice

    = m x latent heat of fusion

    m x 3.35 x 10⁵

    Total heat lost

    = m x 3.35 x 10⁵ + m x 4186 x 50

    = 544300 m

    Heat gained by copper block

    = msΔt

    .3 x 196 x 385 J

    Heat lost = heat gained

    544300 m =.3 x 196 x 385 J

    m = 41.6 gm
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A copper block with a mass of 300 grams is cooled to 77K by being immersed in liquid nitrogen. The block is then placed in a Styrofoam cup ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers