A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d = 5.7 m. Then the mass is pulled up an incline that makes an angle θ = 34° with the horizontal and has a coefficient of kinetic friction μk = 0.48. The entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 34° (thus on the incline it is parallel to the surface) and has a tension T = 62 N. 1) What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Question

Physics

Libby Frye

18 October, 11:01

A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d = 5.7 m. Then the mass is pulled up an incline that makes an angle θ = 34° with the horizontal and has a coefficient of kinetic friction μk = 0.48. The entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 34° (thus on the incline it is parallel to the surface) and has a tension T = 62 N. 1) What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

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Answers (1)

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Fernando Ashley · Answer 1

W ≅ 292.97 J

Explanation:

1) What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;

W = (Fcosθ) d

Given that:

Tension of the force = 62 N

angle of incline θ = 34°

distance d = 5.7 m.

Then;

W = 62 * cos (34) * 5.7

W = 353.4 cos (34)

W = 353.4 * 0.8290

W = 292.9686 J

W ≅ 292.97 J

Hence, the work done by tension before the block goes up the incline = 292.97 J