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11 August, 19:06

The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 70 W. (a) Find the current in the bulb. A (b) Find the bulb's resistance.

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  1. 11 August, 22:13
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    Answer: I = 0.583A

    R=205.83ohms

    Explanation: Power = I*V

    Where I = current and V = potential difference

    I=P/V

    I = 70/120

    I=0.583A

    To find resistance

    Using ohms law

    V = IR

    R=V/I

    R = 120/0.583

    R = 205.83ohms
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