Ask Question
12 April, 10:07

A Roller Derby Exhibition recently came to town. They packed the gym for twoconsecutive weekend nights at South's field house. On Saturday evening, the68-kg Anna Mosity was moving at 17 m/s when she collided with 76-kg SandraDay O'Klobber who was moving forward at 12 m/s and directly in Anna's path. Anna jumped onto Sandra's back and the two continued moving together atthe same speed. Determine their speed immediately after the collision.

+3
Answers (1)
  1. 12 April, 12:53
    0
    14.4 m/s

    Explanation:

    mass of Anna (Ma) = 68 kg

    speed of Anna (Va) = 17 m/s

    mass of SandraDay (Ms) = 76 kg

    speed of SandraDay (Vs) = 12 m/s

    We can find their speed (V) immediately after collision from the conservation of momentum where

    (Ma x Va) + (Ms + Vs) = (Ma + Ms) x V

    where V = speed immediately after collision

    (68 x 17) + (76 + 12) = (68 + 76) x V

    2068 = 144 V

    V = 2068 / 144 = 14.4 m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A Roller Derby Exhibition recently came to town. They packed the gym for twoconsecutive weekend nights at South's field house. On Saturday ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers