Ask Question
8 October, 03:51

A person pushes horizontally with a force of 220. N on a 61.0 kg crate to move it across a level floor. The coefficient of kinetic friction is 0.270. (a) What is the magnitude of the frictional force? (b) What is the magnitude of the crate's acceleration? Use g=9.81 m/s2.

+1
Answers (1)
  1. 8 October, 04:39
    0
    (a) 161.57 N

    (b) 0.958 m/s^2

    Explanation:

    Force applied, F = 220 N

    mass of crate, m = 61 kg

    μ = 0.27

    (a) The magnitude of the frictional force,

    f = μ N

    where, N is the normal reaction

    N = m x g = 61 x 9.81 = 598.41 N

    So, the frictional force, f = 0.27 x 598.41

    f = 161.57 N

    (b) Let a be the acceleration of the crate.

    Fnet = F - f = 220 - 161.57

    Fnet = 58.43 N

    According to newton's second law

    Fnet = mass x acceleration

    58.43 = 61 x a

    a = 0.958 m/s^2

    Thus, the acceleration of the crate is 0.958 m/s^2.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A person pushes horizontally with a force of 220. N on a 61.0 kg crate to move it across a level floor. The coefficient of kinetic friction ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers