A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the process. What is the efficiency of this process?

Question

Physics

Maverick Roth

31 August, 03:13

A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the process. What is the efficiency of this process?

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Answers (1)

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Maya Gallagher · Answer 1

Answer: 83%

Explanation:

Efficiency of the process = work output/work input * 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force * distance

= (3000*10) * 20

= 600000 Joules

Efficiency = 600000/720000 * 100

= 0.83*100

= 83%