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3 August, 05:59

A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. How far did the ball travel before hitting the ground? Round the answer to the nearest tenth of a meter.

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  1. 3 August, 06:43
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    92.1 meters

    Explanation:

    Given:

    x₀ = 0 m

    y = y₀ = 0 m

    v₀ₓ = 31 cos 35° m/s

    v₀ᵧ = 31 sin 35° m/s

    aₓ = 0 m/s²

    aᵧ = - 9.8 m/s²

    Find: x

    First, we need to find the time:

    y = y₀ + v₀ t + ½ at²

    0 = 0 + (31 sin 35) t - 4.9 t²

    t = 0 or (31 sin 35) / 4.9

    Now find x:

    x = x₀ + v₀ t + ½ at²

    x = 0 + (31 cos 35°) (31 sin 35) / 4.9 + 0

    x ≈ 92.1

    The ball travels 92.1 meters.
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