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11 August, 13:04

A cameraman sitting near the open door of a news helicopter accidentally drops his 140-g mobile phone out

the door at an altitude of 990 m. How fast will the phone be falling when it strikes the ground?

A. 9.8 m/s

B. 140 m/s

C. 850 m/s

D. 990 m/s

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Answers (2)
  1. 11 August, 16:40
    0
    140m/s

    Explanation:

    Given parameters:

    Mass of mobile phone = 140g

    Altitude = 990m

    Unknown:

    Final velocity = ?

    Solution:

    This is a motion problem. It is solvable by using the right motion equation. For this problem, understand that the phone is dropping under the influence of gravity.

    V² = U² + 2gH

    where V is the final velocity

    U is the initial velocity

    g is the acceleration due to gravity

    H is the height of fall

    Initial velocity is 0

    Input the variables;

    V² = 0² + 2 (9.8) (990)

    V = 139.29m/s = 140m/s
  2. 11 August, 16:45
    0
    Answer:B. 140 m/s
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