A 50-kg sprinter accelerates from 0 to 11 m/s in 3.0 s. What is the power output for this rapid start?

1008.33 W.

Explanation:

Power: This can be defined as the rate at which energy is consumed or dissipated. The S. I unit of power is Watt (W).

P = E/t ... Equation 1

Where P = Energy, E = Energy, t = time.

But from the question,

E = 1/2mΔv² ... Equation 2

where m = mass of the sprinter, Δv = change in velocity of the sprinter = final velocity - initial velocity.

Substitute equation 2 into equation 1

P = 1/2mΔv/t ... Equation 3

Given: m = 50 kg, Δv = 11-0 = 11 m/s, t = 3.0 s.

Substitute into equation 3

P = 1/2 (50) (11) ²/3

P = 25 (121) / 3

P = 1008.33 W.

Thus the power output = 1008.33 W.