A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway back in 1.8 s. Calculate its average speed for the entire trip.

Express your answer using two significant figures.

Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction.

Express your answer using two significant figures.

Average velocity = 1.69 m/s

Average speed = 5.09 m/s

Explanation:

Given that

Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.

As we know that

Average velocity = Displacement / Total time

Average speed = Total distance / Total time

Average velocity:

Average velocity = Displacement / Total time

Total displacement = 37 - 18.5 = 18.5 m

Total time = 9.1 + 1.8 = 10.9 s

Average velocity = Displacement / Total time

Average velocity = 18.5 / 10.9

Average velocity = 1.69 m/s

Average speed:

Average speed = Total distance / Total time

Total distance = 37 + 18.5 = 55.5 m

Total time = 9.1 + 1.8 = 10.9 s

Average speed = Total distance / Total time

Average speed = 55.5 / 10.9

Average speed = 5.09 m/s