A bike accelerates uniformly from rest to a speed of 8.59 m/s over a distance of 28.4m. Determine the acceleration of the bike.

1.3m/s^2

Explanation:

Data obtained from the question include:

U (initial velocity) = 0m/s

V (final velocity) = 8.59 m/s

s (distance) = 28.4m

a (Acceleration) = ?

Using the equation of motion (v^2 = u^2 + 2as), the acceleration can be obtain as follows:

v^2 = u^2 + 2as

(8.59) ^2 = 0 + 2 x a x 28.4

73.7881 = 56.8a

Divide both side by the coefficient of a i. e 56.8

a = 73.7881/56.8

a = 1.3m/s^2

Therefore, the acceleration of the bike is 1.3m/s^2

1.3m/s²

Explanation:

Initial speed: vo=0m/s

Final speed: vf=8.59m/s

Distance: d=28.4m

vf²=vo²+2*a*d (Galilei's formula)

a = (vf²-vo²) / 2/d=8.59²/2/28.4=1.3m/s²