A 6.0 mw vertically polarized laser beam passes through a polarizing filter whose axis is 75° from vertical. What is the laser-beam power after passing through the filter?

I = 0.4019 m W

Explanation:

given,

Beam of light Intensity = 6.0 m W

angle made with the vertical = 75°

Power of the laser beam passing through filter = ?

using formula

I = I₀ cos² (θ)

I is the intensity required

I₀ is the initial intensity of light

I = I₀ cos² (θ)

I = 6 x cos² (75°)

I = 6 x 0.0669

I = 0.4019 m W

Laser beam power after passing through filter is equal to I = 0.4019 m W