Ask Question
13 December, 03:07

In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 17 m/s2. What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

+2
Answers (1)
  1. 13 December, 05:13
    0
    coefficient of static friction is 1.7329

    Explanation:

    given data

    velocity = 60 mph

    acceleration = 17 m/s²

    to find out

    coefficient of static friction

    solution

    we will apply here centripetal force equation

    that is

    m*v²/r = µ * m * g ... 1

    here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so

    µ = a / g

    µ = 17 / 9.81

    µ = 1.7329

    so coefficient of static friction is 1.7329
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers