When tuning his guitar, a music student notices that the string is not vibrating at the desired frequency of 120 Hz, so he tightens the string by 15.5% to get this frequency. At what frequency was the string vibrating when he first started the tuning process

Question

Physics

Mclean

15 November, 14:03

When tuning his guitar, a music student notices that the string is not vibrating at the desired frequency of 120 Hz, so he tightens the string by 15.5% to get this frequency. At what frequency was the string vibrating when he first started the tuning process

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Answers (1)

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Giada Mercado · Answer 1

We know that

frequency ∝ √ Tension

So

Δn / n = 1/2 (ΔT / T)

Δn / n =.155 / 2 (GIVEN)

=.0775

Δn =.0775 n

Let the original frequency be n

n + Δn = 120

n +.0775 n = 120

n = 111.36