An aluminum baseball bat has a length of 0.661 m at a temperature of 12.4°C. When the temperature of the bat is raised, the bat lengthens by 0.000172 m. Determine the final temperature of the bat.

T=23.713 C

Explanation:

Knowing the bat lengthens by 0.000172m and the initial temperature 12.4 C to find the final temperature use the equation of length:

ΔL = α * Lo * ΔT

α=23x10^-6 C Aluminum constant

T = To + ΔT

ΔT = ΔL / α * Lo

T = To + ΔL / α * Lo

T = 12.4 C + 0.172x10^-3m / 23x10^-6C * 0.661m

T=23.713 C