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2 July, 23:28

A 4-A current is maintained in a simple circuit with a total resistance of 2 Ω. How much energy is dissipated in 3 seconds?

A) 3 J

B) 6 J

C) 12 J

D) 24 J

E) 96 J

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Answers (1)
  1. 3 July, 01:56
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    Answer: Energy dissipated E = 96J

    Explanation:

    Given:

    Current I = 4A

    Resistance R = 2 Ohms

    Time t = 3 seconds

    The energy dissipation in an electric circuit can be derived from the equation below:

    E = IVt ... 1

    Where;

    I = current, V = Voltage (potential difference), t = time and E = energy dissipated

    But we know that;

    V = I*R ... 2

    Substituting equation 2 to 1, we have

    E = IVt = I (I*R) t = I^2 (Rt)

    Substituting the values of I, R and t

    E = 4^2 * 2 * 3 = 96J

    Energy dissipated E = 96J
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