A block slides down a frictionless inclined ramp. If the ramp angle is 12° and its length is 10 m, find the speed of the block as it reaches the bottom of the ramp, assuming it started sliding from rest at the top.

v = 6.44 m/s

Explanation:

Given that

L = 10 m

θ = 12°

The block slides due to gravitational force.

The gravitational force along the incline ramp = m g sinθ

Lets take a is the acceleration of the block along the ramp

m a = m g sinθ

a = g sinθ

The equation of motion along the incline plane

Lets take final speed = v m/s

Initial speed u = 0 m/s

v² = v² + 2 a L

v² = 2 x g sinθ x L

v² = 2 x 10 x sin12° x 10 (take g = 10 m/s²)

v² = 41.58

v = 6.44 m/s