If the gas mileage of a Honda Civic car is 38 miles per gallon how many liters of gasoline would the car use to move from the Essex campus to the Catonsville campus? The distance between the two campuses is 37.2 km. (Do not show units in your answer).

6.25

Explanation:

M = d/g ... Equation 1

making g the subject of the equation,

g = d/M ... Equation 2

Where M = mileage per gallon, d = distance move from Essex campus to Catonsville campus, g = amount of gasoline used

Given: M = 38 miles per gallon, d = 37.2 km

If 1 kilometer = 0.62 miles

Then, 37.2 km = 37.2*0.62 miles = 23.064 miles

Substituting these values into equation 2,

g = 38/23.064

g = 1.648 gallon

g ≈1.65 gallon

Thus,

If, 0.264 gallon = 1 liters.

Then, 1.65 gallon = 1.65*1/0.264 = 6.25 liters.

g = 6.25

Thus the car will use 6.25 liters of gasoline to move from the Essex campus to the Catonsville campus.