What is the change in temperature of a 2.50 L system when its volume is reduced to 1.00 L if the initial temperature was 298 K?

-178.8 K

Explanation:

From Charles law,

V₁/T₁ = V₂/T₂ ... Equation 1

Where V₁ = Initial volume, T₁ = Initial Temperature, V₂ = Final volume, T₂ = Final Temperature.

Making T₂ the subject of the equation

T₂ = V₂T₁/V₁ ... Equation 2

Given: V₂ = 1.00 L, V₁ = 2.5 L, T₁ = 298 K.

Substitute into equation 2

T₂ = 1.00 (298) / 2.5

T₂ = 119.2 K.

But,

Change in temperature = T₂ - T₁ = 119.2-298

Change in temperature = - 178.8 K.

Hence the change in temperature = - 178.8 K