Based on its location on the periodic table which element would be most likely to form a negative ion

This question is incomplete but the completed question is below

Based on its location on the periodic table, which element would be most likely to form a negative ion?

A. Aluminum (Al)

B. Copper (Cu)

C. Sodium (Na)

D. Fluorine (F)

The correct option is D

Explanation:

An atom will become negatively charged when it accepts/gains electron (s). Atoms lose/gain electrons in order to achieve there octet configuration. In the periodic table, metals donate/lose their valence electron (s) to become positively charged (cation) while non-metals accept/gain electron (s) to become negatively charged (anion).

From the explanation above, it can be deduced that aluminium (Al) will lose the three valence electrons in it's outermost shell to become Al³⁺, copper (Cu) will lose two valence electrons to become Cu²⁺ while sodium (Na) will lose the only electron it has on its outermost shell to become Na⁺.

Fluorine (F), a non-metal, however gains an electron to become a negatively charged ion (F⁻).