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24 October, 22:14

A straight wire carrying a 3.30-A current is placed in a uniform magnetic field of magnitude 0.272 T directed perpendicular to the wire. (a) Find the magnitude of the magnetic force on a section of the wire having a length of 12.7 cm. N (b) Explain why you can't determine the direction of the magnetic force from the information given in the problem

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  1. 25 October, 01:07
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    F = 0.114 N

    Explanation:

    a) The magnetic force is given by the equations

    F = q v x B = I Lx B

    the bold incate vector. This equation can be used in the form of magnitude and find the direction separately with the rule of the right hand

    F = i L B sin θ

    Where θ is the angle between the direction (L) and the magnetic field, if the two are perpendicular sin 90 = 1

    Let's calculate

    F = 3.30 0.127 0.272

    F = 0.114 N

    b) to know the direction of the magnetized field we must know the direction of B and L, but in the problem they tell us that they are perpendicular, but not the direction of each
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