Ask Question
29 August, 20:05

The electric field strength is 20,000 N/C inside a parallel-plate capacitor with a 1.0 mm spacing. An electron is released from rest at the negative plate. What is the electron's speed when it reaches the positive plate?

0
Answers (1)
  1. 29 August, 21:52
    0
    The electron's speed when it reaches the positive plate is 2.65 X 10⁶m/s

    Explanation:

    Electric field strength, E = 20,000 N/C

    Distance, x = 1 mm = 1 X 10⁻³m

    Speed of the electron, s = ?

    We know,

    Charge of an electron, q = 1.602 X 10⁻¹⁹ C

    So the force, F is

    20000 N/C x 1.602 X 10⁻¹⁹ C = 3.2 X 10⁻¹⁵ Newtons

    mass of electron is 9.1*10⁻³¹ kg

    F = ma

    a = 3.2 X 10⁻¹⁵ / 9.1 X 10⁻³¹ = 3.52 X 10¹⁵ m/s²

    v = √ (2ad) = √ (2*3.52 X 10¹⁵ X 0.001) = 2.65 X 10⁶m/s

    Therefore, the electron's speed when it reaches the positive plate is 2.65 X 10⁶m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The electric field strength is 20,000 N/C inside a parallel-plate capacitor with a 1.0 mm spacing. An electron is released from rest at the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers