Ask Question
22 October, 01:50

A 2-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ.

+1
Answers (1)
  1. 22 October, 05:05
    0
    Power (p) = 2kW

    Time (t) = 3 h

    Work done (w) = ?

    p = w / t

    w = p * t

    w = 2kW * 3 h

    w = 6kWh

    Converting 6kWh to Joules,

    6kWh

    6 * (10^3) h (k = 10^3)

    6*10^3 * (60*60) (1 hour = 60 * 60 sec)

    2.2*10^7 J in 2 significant figures
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 2-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the amount of ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers