Ask Question
9 May, 13:20

A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of 32.1 m/s at an angle of 60.0° above the horizontal. How high will the ball rise than where it was hit?

+5
Answers (1)
  1. 9 May, 14:56
    0
    Maximum height reached = 39.39 m

    Explanation:

    At maximum height

    We have equation of motion v² = u² + 2as

    Consider the vertical motion of baseball,

    Initial velocity, u = 32.1sin60=27.8 m/s

    Final velocity, v = 0 m/s

    Acceleration, a = - 9.81 m/s²

    Substituting

    v² = u² + 2as

    0 = 27.8² + 2 x (-9.81) x s

    s = 39.39 m

    Maximum height reached = 39.39 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from which it was ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers