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17 January, 11:16

A platinum ball weighing 100 g is removed from a furnace and dropped into 400 g of water at 0 degree C. If the equilibrium temperature is 10 degrees C, and the specific heat of platinum is 0.04 cal/g degree C, what must have been the temperature of the furnace? Neglect the effect of the mass of the calorimeter.

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  1. 17 January, 13:13
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    T = 1010 degree Celsius

    Explanation:

    mass of ball (Mb) = 100 g

    mass of water (Mw) = 400 g

    temp of water = 0 degree

    specific heat of platinum (C) = 0.04 cal/g degree celsius

    we can calculate the temperature of the furnace from the equation before

    Mb x C x (temp of furnace (T) - equilibrium temp) = Mw x (equilibrium temp - temp of furnace)

    100 x 0.04 x (T - 10) = 400 x (10 - 0)

    4 (T - 10) = 4000

    T - 10 = 1000

    T = 1010 degree Celsius
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