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28 November, 21:01

A 0.10-kilogram ball dropped vertically from a height of 1.0 meter above the floor bounces back to a height of 0.80 meter. The mechanical energy lost by the ball as it bounces is approximately

A) 0.20 J

B) 0.080 J

C) 0.78 J

D) 0.30 J

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  1. 28 November, 23:46
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    A) 0.20Joules

    Explanation:

    The type mechanical energy acting on the body is potential energy since the body is covering a particular height.

    Potential Energy = mass*acceleration due to gravity * height

    Mass of the body = 0.1kg

    acceleration due to gravity = 10m/s²

    h is the height of the object when dropping = 1.0meters

    Substituting this values in the formula to get the energy of the body on dropping, we have;

    PE = 0.1*10*1.0

    PE = 1.0Joules

    On bouncing back to height of 0.8m, the potential energy becomes

    PE = 0.1*10*0.8

    PE = 0.8Joules

    The mechanical energy lost by the ball as it bounces will approximately be the difference in its potential energy when dropping and when it bounces back i. e 1.0Joules - 0.8Joules = 0.20Joules
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