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11 September, 12:16

To determine the specific heat of an object, a student heats it to 100 degrees C in boiling water. She then places the 110 g object in a 172 g aluminum calorimeter containing 148 g of water. The aluminum and water are initially at a temperature of 19.6 degrees, and are thermally insulated from their surroundings.

If the final temperature is 23.8 degrees, what is the specific heat of the object?

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  1. 11 September, 16:01
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    Cs=912.6J/kg/K

    Explanation:

    Sum of Heat gained=sum heat lośs

    Definition of terms

    Ms=mass of substance 0.11kg

    Cs=specific heat capacity of the substance?

    Ts = temperature of the substance

    Tm = temperature of mixture 28.8°C

    Tal = temperature of aluminium19.6°C

    Tw=temperature of water 19.6°C

    Mal=mass of aluminium 0.172kg

    Mw=mass of water 0.148kg

    Cw = specific heat capa of water 4200j/kgk

    Cal=specific heat capacity of aluminium 903j/kgk

    Having gotten all the parameters needed

    Ms*Cs * (Ts-Tm) = Mw*Cw * (Tm-Tw) + Mal*Cal * (Tm-Tal)

    0.11*Cs * (100-28.8) = 0.148*4200 * (28.8-19.6) + 0.172*903 * (28.8-19.6)

    cs= = ((4467267) / (4895))

    Cs=912.61Jkg-1K-1
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