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5 May, 15:31

Two cars are traveling along a straight road. Car A maintains a constant speed of 95 km/h and car B maintains a constant speed of 121 km/h. At t = 0, car B is 41 km behind car A.

(a) How much farther will car A travel before car B overtakes it? km

(b) How much ahead of A will B be 30 s after it overtakes A? km

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  1. 5 May, 17:51
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    Answer

    given,

    Speed of car A = 95 Km/h

    = 95 x 0.278 = 26.41 m/s

    Speed of Car B = 121 Km/h

    = 121 x 0.278 = 33.64 m/s

    Distance between Car A and B at t=0 = 41 Km

    a) Distance travel by car B

    d = 26.41 t + 41000

    speed of the car A = 33.64 m/s

    distance = s x t

    26.41 t + 41000 = 33.64 x t

    7.23 t = 41000

    t = 5670.82 s

    time taken by Car B to cross Car A is equal to t = 5670.82 s

    distance traveled by car A

    D = s x t = 26.41 x 5670.82 = 149766.25 m = 149.76 Km

    b) distance travel by the car B in 30 s after overtaking car A

    D' = s x t = 33.64 x 30 = 1009.2 m = 1 Km
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