A 4.9 A current is set up in a circuit for 5.4 min by a rechargeable battery with a 6.0 V emf. By how much is the chemical energy of the battery reduced?

E = 9525.6 J

Explanation:

Given that

Current, I = 4.9 A

time, t = 5.4 min

Voltage difference,ΔV = 6 V

energy delivered by battery in time t is given as

E=V I t

where V is voltage, I is the current and t is the time.

now putting the values in above equation

E = 6 x 4.9 x 5.4 x 60 J (1 min = 60 s, 5.4 min = 5.4 x 60 s)

E = 9525.6 J

Therefore the energy reduced will be 9525.6 J