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29 April, 01:37

A 2.9 * 103 kg car accelerates from rest under the action of two forces. One is a forward force of 1148 N provided by traction between the wheels and the road. The other is a 941 N resistive force due to various frictional forces. How far must the car travel for its speed to reach 2.7 m/s? Answer in units of m.

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  1. 29 April, 02:08
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    The car must travel 51.34 m for its speed to reach 2.7 m/s

    Explanation:

    Mass of car = 2.9 x 10³ kg

    Forward force = 1148 N

    Resistive force = 941 N

    Total force = 1148 - 941 = 207 N

    We know

    Force = Mass x Acceleration

    207 = 2.9 x 10³ x Acceleration

    Acceleration = 0.071 m/s²

    Now we have equation of motion, v² = u² + 2as

    Initial velocity, u = 0 m/s

    Final velocity, v = 2.7 m/s

    Acceleration, a = 0.071 m/s²

    Substituting

    v² = u² + 2as

    2.7² = 0² + 2 x 0.071 x s

    s = 51.34 m

    The car must travel 51.34 m for its speed to reach 2.7 m/s
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