Ask Question
24 September, 03:07

An SUV with a mass of 1.80 103 kg is travelling eastbound with a speed of 15.0 m s while a compact car with a mass of 9.00 102 kg is travelling westbound at 15.0 m s The vehicles collide head on and stick together What is the speed of the wreck immediately after the collision and which way does it move

+1
Answers (1)
  1. 24 September, 03:38
    0
    5 m/s

    Explanation:

    mass of SUV (M1) = 1.80 x 10^{3} kg = 1800 kg

    velocity of SUV (V1) = 15 m/s

    mass of car (M2) = 9 x 10^{2} kg = 900 kg

    velocity of car (V2) = 15 m/s

    let the direction of motion eastward (to the right) be positive while the direction of motion westward (to the left) be negative, therefore

    velocity of SUV (V1) = 15 m/s

    velocity of car (V2) = - 15 m/s

    now applying the conservation of momentum

    (M1) (V1) + (M2) (V2) = (M1 + M2) x Vf

    where Vf is the final velocity after collision

    (1800 x 15) + (900 x (-15)) = (1800 + 900) x Vf

    27000 - 13500 = 2700Vf

    13500 = 2700 Vf

    Vf = 5 m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “An SUV with a mass of 1.80 103 kg is travelling eastbound with a speed of 15.0 m s while a compact car with a mass of 9.00 102 kg is ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers