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11 November, 15:40

The initial position and velocity of a projectile are given by r₀ = 3i+4j and v₀ = 6i+8j respectively, and where r is in m and v in m/s. The position in the horizontal direction (in m) as a function of time is:

A. x (t) = 6t

B. x (t) = 4 + 8t

C. x (t) = 3 + 6t + The initial position and velocity of a projectile gt²

D. x (t) = 3 + 6t

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Answers (1)
  1. 11 November, 17:35
    0
    x (t) = 3 + 6*t

    Option D

    Explanation:

    Given:

    - Position vector r_o = 3 i + 4 j

    - Initial velocity vector v_o = 6 i + 8 j

    Find:

    The position in the horizontal direction (in m) as a function of time is:

    Solution:

    - Using second kinematics equation of motion we have:

    x (t) = x_o + v_o, x*t

    Where,

    x_o : is the initial position in x direction

    v_o, x : is the initial velocity in x direction.

    From given vectors we have x_o = 3 and v_o, x = 6

    Hence, x (t) = 3 + 6*t is the equation of horizontal position.
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