Ask Question
20 May, 11:50

Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 of 1190°C fresh lava into 30.0°C surroundings, assuming lava's emissivity is 1.

+5
Answers (1)
  1. 20 May, 12:00
    0
    259.274 kW

    Explanation:

    Given:

    Area of the lava, A = 1.00 m²

    Temperature of the surrounding, T₁ = 30.0° C = 303 k

    Temperature of the lava, T₂ = 1190° C = 1463 K

    emissivity, e = 1

    Now,

    from the Stefan-Boltzmann law of radiation the rate of heat loss is given as,

    u = σeA (T₂⁴ - T₁⁴)

    where,

    u = rate of heat loss

    σ = Stefan-Boltzmann constant = 5.67 * 10⁻⁸ W/m²∙K⁴

    on substituting the respective values, we get

    u = 5.67 * 10⁻⁸ * 1 * 1 * (1463⁴ - 303⁴)

    or

    u = 259274.957 W

    or

    u = 259.274 kW
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 of 1190°C ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers