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19 November, 16:53

A loudspeaker diaphragm is vibrating in simple harmonic motion with a frequency of 760 Hz and a maximum displacement of 0.85 mm.

(a) What is the angular frequency?

(b) What is the maximum speed?

(c) What is the maximum acceleration?

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Answers (1)
  1. 19 November, 19:06
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    Answer: (a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²

    Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm = 0.00085m

    (a) Angular frequency w = 2πf

    w = 2π * 760 = 4775.2Hz

    (b) Maximum speed v is given as the product of angular frequency and maximum displacement

    V=wx

    V = 4775.2 * 0.00085

    V = 4.06m/s

    (c) The maximum acceleration a

    = w²x

    = (4775.2) ² * (0.00085)

    a = 19382.15m/s².
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