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31 March, 17:53

A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.0 cm deep. How far upward from its initial position does the mercury in the right arm rise?

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  1. 31 March, 18:20
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    0.368 cm

    Explanation:

    x = distance by which the mercury rise

    d = depth of the water = 10 cm = 0.10 m

    ρ = density of water = 1000 kgm⁻³

    ρ' = density of mercury = 13600 kgm⁻³

    P₀ = atmospheric pressure

    Using equilibrium of pressure on both side

    P₀ + ρ g d = P₀ + ρ' g (2x)

    (1000) (0.10) = (13600) (2x)

    x = 0.00368 m

    x = 0.368 cm
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